How are 2D static arrays allocated?

[ore-sama]

Jarrett Billingsley Wrote:

> You.. can't actually allocate a static array on the heap using new.
> At least not directly.  It's kind of an embarrassing hole in the
> syntax.  In fact, I'm not sure if you can even get a static array to
> point onto the heap, since a static array "reference" is treated like
> a value type when assigned to, so if you do something like:
> 
> int[3][4] b = (new int[3][4][](1))[0];
> 
> The weirdness on the right-hand-side is needed to get around the
> compiler "helpfully" rewriting "new int[3][4]" as "new int[][](3, 4)".
>  But this code will simply allocate a static array on the heap, and
> then copy its contents onto the stack.  Dumb.
	auto rg2=new int[10][20];
	writeln(typeof(rg2).stringof); //int[10u][]
	writeln(cast(size_t)&rg2[1]-cast(size_t)&rg2[0]); //40

As you can see it allocates contunous int[10][20] and assigns it to dynamic array int[10][]. Which is nearly what topicstarter wants. Well, border checks will be dynamic for the first index.