Error: template std.conv.parse cannot deduce function from argument types

[Ralph Doncaster]

On Tuesday, 6 February 2018 at 17:47:30 UTC, Adam D. Ruppe wrote:
> On Tuesday, 6 February 2018 at 17:33:43 UTC, Ralph Doncaster 
> wrote:
>> I get this error when I try the following code:
>
> parse specifically works with a reference input it can advance. 
> From the docs:
>
> "It takes the input by reference. (This means that rvalues - 
> such as string literals - are not accepted: use to instead.)
> It advances the input to the position following the conversion."
>
>> I think the template overloading for parse is getting confused 
>> because it sees the lvalue r.l as being of type union rather 
>> than ulong.
>
> The left hand side of an assignment never plays a role in 
> overloading, so you can disregard that. It is just a string 
> literal cannot be advanced and thus does not work with parse.

Thanks!  Got it.