How to instantiate a template struct with a template constructor without relying on auto deduction?

[Simen Kjærås]

On Wednesday, 21 February 2018 at 14:29:38 UTC, ixid wrote:
> I do not understand what is happening here, I tried to wrote 
> what I thought would be the answer. If someone could explain 
> that would be great. I wrote this code:
>
> struct Foo2(T, S) {
>   T bar;
>   this(S s) {
>     bar = s.to!T;
>   }
> }
>
> void main() {
> 	float some_float = 0.5f;
> 	int some_int = 1;
>
> 	auto foo1 = Foo2!(int, float)(some_float);    // Compiles, OK!
> 	auto foo2 = Foo2!(int, float)(some_int);      // Compiles, wat?
> }

int n = 1;
float f = n; // Basically this.

Foo2!(int, float) expects a float, and ints are implicitly 
convertible to float.

--
   Simen