How to instantiate a template struct with a template constructor without relying on auto deduction?

[ixid]

On Wednesday, 21 February 2018 at 14:42:56 UTC, Simen Kjærås 
wrote:
> On Wednesday, 21 February 2018 at 14:29:38 UTC, ixid wrote:
>> I do not understand what is happening here, I tried to wrote 
>> what I thought would be the answer. If someone could explain 
>> that would be great. I wrote this code:
>>
>> struct Foo2(T, S) {
>>   T bar;
>>   this(S s) {
>>     bar = s.to!T;
>>   }
>> }
>>
>> void main() {
>> 	float some_float = 0.5f;
>> 	int some_int = 1;
>>
>> 	auto foo1 = Foo2!(int, float)(some_float);    // Compiles, OK!
>> 	auto foo2 = Foo2!(int, float)(some_int);      // Compiles, 
>> wat?
>> }
>
> int n = 1;
> float f = n; // Basically this.
>
> Foo2!(int, float) expects a float, and ints are implicitly 
> convertible to float.
>
> --
>   Simen

Ah yes, that was silly of me to forget. Thanks!