Why is typeof(readln) -> void?
rikki at cattermole.co.nz
Sat Jul 18 09:49:19 UTC 2020
On 18/07/2020 9:14 PM, blizzard wrote:
> Can anybody explain the difference between readln() and readln? I read
> somewhere that the () were optional, so why this difference?
The brackets are optional when calling a function. You are not calling a
function if you wrap it in typeof.
"The Expression is not evaluated, it is used purely to generate the type:"
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