Why is typeof(readln) -> void?

rikki cattermole rikki at cattermole.co.nz
Sat Jul 18 09:49:19 UTC 2020

On 18/07/2020 9:14 PM, blizzard wrote:
> Can anybody explain the difference between readln() and readln? I read 
> somewhere that the () were optional, so why this difference?

The brackets are optional when calling a function. You are not calling a 
function if you wrap it in typeof.

"The Expression is not evaluated, it is used purely to generate the type:"


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