How can I test at compile time whether T is an instance of an interface ?
invalid at example.com
Wed Sep 23 18:37:45 UTC 2020
I have some similar functions:
void register(C: IFoo)()
void register(C)() if (behavesLikeFoo!C)
There are more overloads with parameters so I want to merge them
void register(C, ARGS...)(ARGS args) if (behavesLikeFoo!C ||
I found a lot of information on how to do this at runtime but not
at compile time.
std.traits: isInstanceOf doesn't work. Neither did anything I
tried with typeid etc.
The behavesLikeFoo constraint works as expected but it accepts
any class no matter whether or not it implements the interface.
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