How can I test at compile time whether T is an instance of an interface ?
data.pulverizer at gmail.com
Wed Sep 23 18:49:28 UTC 2020
On Wednesday, 23 September 2020 at 18:37:45 UTC, wjoe wrote:
> I have some similar functions:
> void register(C: IFoo)()
> void register(C)() if (behavesLikeFoo!C)
> There are more overloads with parameters so I want to merge them
> void register(C, ARGS...)(ARGS args) if (behavesLikeFoo!C ||
> isInstanceOf!(C, IFoo))
> I found a lot of information on how to do this at runtime but
> not at compile time.
> std.traits: isInstanceOf doesn't work. Neither did anything I
> tried with typeid etc.
> The behavesLikeFoo constraint works as expected but it accepts
> any class no matter whether or not it implements the interface.
A class at compile time is it's own static type, OOP polymorphism
is a runtime feature not compile time. You have to write your own
traits for specific objects to get them to relate to each other
using static overloading.
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