Reference to an object disregarding mutation - what's the trick?
Regan Heath
regan at netmail.co.nz
Mon May 28 15:10:24 PDT 2007
Manfred Nowak Wrote:
> Steve Teale wrote
>
> > how do I get the semantics I'd get with a plain old pointer to the
> > object?
>
> You cannot use?:
> Node[]* t = &node.parent.nodelist;
Manfreds rather brief reply is exactly what I was going to suggest. The nice thing about D is that a struct, class, pointer, reference, pointer to pointer or reference, pointer to pointer to .. you get the idea; all get de-referenced by the '.' operator, there is no silly '->' operator for pointers.
So, by taking a pointer to the reference you should be able to modify the reference via the pointer by saying:
int n = t.length;
t.length = n+1;
or
t.length = t.length+1;
Regan Heath
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