Get name of alias parameter at compile time?

[dsimcha]

== Quote from Lutger (lutger.blijdestijn at gmail.com)'s article
> Denis Koroskin wrote:
> > On Thu, 15 Oct 2009 18:22:37 +0400, dsimcha <dsimcha at yahoo.com> wrote:
> >
> >> Jacob Carlborg Wrote:
> >>
> >>> On 10/14/09 06:36, dsimcha wrote:
> >>> > Is there a way to get the name of an alias parameter at compile
> >>> time?  For
> >>> > example:
> >>> >
> >>> > void doStuff() {
> >>> >      // Do stuff.
> >>> > }
> >>> >
> >>> > void templ(alias fun)() {
> >>> >     writeln(fun.stringof);  // Prints doStuff.
> >>> > }
> >>>
> >>> Do you want that to print "fun" instead of "doStuff"?
> >>
> >> No, the whole point is that I want to print "doStuff".
> >
> > What's the big deal?
> >
> > import std.stdio;
> >
> > void doStuff() {
> > }
> >
> > void templ(alias fun)() {
> >      writeln(fun.stringof);   // prints "main()"
> > }
> >
> > void main()
> > {
> >      templ!(main);
> > }
> >
> > Works for both D1 and D2
> I was a bit surprised too since the code dsimcha posted did exactly that.
> However, change void doStuff() to void doStuff(int a) and you got an error.
> I remembered hacking around that one, if anybody knows how to do it better
> it would be good to know:
> void doStuff(int a)
> {
> // Do stuff.
> }
> void templ(T...)()
>     if (T.length==1)
> {
>     writeln( T.stringof[6..$-1] );
> }
> void main()
> {
>     templ!doStuff();
> }

Yeah, now that I look into it further, what you describe is exactly the problem.
The obvious way only works for functions w/o parameters.  I simplified my example
before I posted it and never bothered to test it.