Jérôme M. Berger Wrote: > > -3 mod 3 = 0 > > -2 mod 3 = -2 > > -1 mod 3 = -1 > > 0 mod 3 = 0 > > Note that from a strictly mathematical point of view, this result > is valid: for all x and all n, x-(x%n) is a multiple of n. It's rather (x/n)+(x%n)==x