modulus and array.length

["Jérôme M. Berger"]

Kagamin wrote:
> Jérôme M. Berger Wrote:
> 
>>> -3 mod 3 = 0
>>> -2 mod 3 = -2
>>> -1 mod 3 = -1
>>> 0 mod 3 = 0
>> 	Note that from a strictly mathematical point of view, this result
>> is valid: for all x and all n, x-(x%n) is a multiple of n.
> 
> It's rather (x/n)+(x%n)==x

	That is (part of) the definition of the *remainder* operation. The
definition of *modulus* is looser.

		Jerome
-- 
mailto:jeberger at free.fr
http://jeberger.free.fr
Jabber: jeberger at jabber.fr

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