reference to 'self' inside a function

[Rob T]

This is a little insane, but it works.

int Recurse(int a)
{
    if (a <= 1)
       return 1;
    else
    // can we replace explicit call to "Recurse"
    // with "self" using a mixin or some other means?
    //   return a * Recurse(a - 1);
       mixin("return a * mixin(__traits(identifier, 
__traits(parent, {})))(a - 1);");
}

--rt

On Tuesday, 25 September 2012 at 04:42:43 UTC, Rob T wrote:
> On Sunday, 23 September 2012 at 17:15:13 UTC, Ben Davis wrote:
>> Here's another one that might work, and be less error-prone:
>>
>> mixin template Self() {
>>  auto self = __traits(identifier, __traits(parent, {}));
>> }
>>
>> void test() {
>>  mixin Self;
>>  writeln(self);
>> }
>>
>
> OK, we've managed to get the calling function symbol name 
> without re-specifying it. Now I wonder if we can perform mixin 
> magic to execute a function recursively without re-specifying 
> the function name?
>
> Example recursive function
>
> int Recurse(int a)
> {
>    if (a <= 1)
>       return 1;
>    else
>    // can we replace explicit call to "Recurse"
>    // with "self" using a mixin or some other means?
>       return a * Recurse(a - 1);
> }
>
>
> We could try and get the function pointer, but that seems like 
> the wrong approach. I'd rather get the function name, do some 
> mixin magic with it to generate the compile time code that uses 
> the function name directly. Can we mixin a mixin???
>
> --rt