Transforming a range back to the original type?

[Jakob Ovrum]

On Friday, 4 May 2012 at 19:17:13 UTC, Steven Schveighoffer wrote:
> This one:
>
> Collection c = new Collection();
> c = c.filter!(x => x < 3).toCollection();
>
> filter isn't a property of c, it's a range-producing function.  
> So I only have to define filter once, as a range accepting, 
> range producing function.  And any container type, as long as 
> it can produce a range, can use this as a pseudo method (via 
> UFCS) to make a filtered copy of itself.
>
> -Steve

That's not a real example, that's pretty much the same example I 
provided below the part you quoted.