They are not the same
bearophile
bearophileHUGS at lycos.com
Fri Apr 4 18:28:05 PDT 2014
Can you spot the difference between foo1 and foo2?
import std.algorithm: map;
import std.range: iota;
void foo1(in int[] a, in int[] b) pure {
int[] r;
foreach (immutable i; 0 .. a.length)
r ~= (i % 2) ? a[i] : b[i];
}
void foo2(in int[] a, in int[] b) pure {
int[] r;
foreach (x; iota(a.length)
.map!(i => (i % 2) ? a[i] : b[i]))
r ~= x;
}
void main() {}
Sometimes variants of this problem hit me. I don't even know if
this simple problem has a name. Is it impossible to solve?
Bye,
bearophile
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