They are not the same
Meta
jared771 at gmail.com
Fri Apr 4 18:57:57 PDT 2014
On Saturday, 5 April 2014 at 01:28:06 UTC, bearophile wrote:
> Can you spot the difference between foo1 and foo2?
>
>
> import std.algorithm: map;
> import std.range: iota;
>
> void foo1(in int[] a, in int[] b) pure {
> int[] r;
> foreach (immutable i; 0 .. a.length)
> r ~= (i % 2) ? a[i] : b[i];
> }
>
> void foo2(in int[] a, in int[] b) pure {
> int[] r;
> foreach (x; iota(a.length)
> .map!(i => (i % 2) ? a[i] : b[i]))
> r ~= x;
> }
>
> void main() {}
>
>
>
> Sometimes variants of this problem hit me. I don't even know if
> this simple problem has a name. Is it impossible to solve?
>
> Bye,
> bearophile
When I put a println inside both functions, they both print out
[2, 1, 0]. Shouldn't the first print [0, 1, 2] while the second
prints [2, 1, 0]?
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