Breaking ";" rule with lambda functions

[Ivan Kazmenko]

On Monday, 1 August 2022 at 20:36:12 UTC, pascal111 wrote:
> My complaint is about that a function is not a same as an 
> expression that functions return values, but expressions being 
> evaluated to provide values.

An analogy.

With a ternary expression, we write:
`x = (cond ? a : b);`
The traditional look of it is:
`if (cond) x = a; else x = b;`
Note how we have a semicolon after `x = a` in the latter form, 
but can't have it in the former.

Ivan Kazmenko.