How to construct a struct that does not explicitly define a constructor

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On Saturday, 1 March 2025 at 00:47:20 UTC, Paul Backus wrote:
> What you can do is use curly-brace initialization syntax:
>
> ```d
> struct Test
> {
>     int n;
>     float f;
>
>     static Test opCall(int n, float f)
>     {
>         Test result = { n, f };
>         return result;
>     }
> }
>
> void main()
> {
>     auto test = Test(1, 2.0);
>     assert(test.n == 1);
>     assert(test.f == 2.0);
> }
> ```

Thanks, I forgot about that syntax. Another question I have is if 
there's a way to do this inline:

```d
struct Test
{
     int n;
     float f;

     static Test opCall(int n, float f)
     {
         //return {n, f};            Error
         //return Test {n, f};       Error
         //return {n: n, f: f};      Error
         //return Test {n: n, f: f}; Error
     }
}

void main()
{
     auto test = Test(1, 2.0);
     assert(test.n == 1);
     assert(test.f == 2.0);
}
```