invariant()

[davidl]

在 Sun, 12 Apr 2009 20:57:28 +0800，Michel Fortin  
<michel.fortin at michelf.com> 写道:

> In D1 you had to write:
>
> 	invariant
> 	{
> 		...
> 	}
>
> while in D2, to disabiguate with invariant being overloaded with  
> immutability you had to write:
>
> 	invariant()
> 	{
> 		...
> 	}
>
> Now that the use of the invariant keyword in D2 has returned to its  
> single original meaning of class invariant, is there still a reason for  
> it to require an empty parenthesis? Should I fill a bug?
>

It will be good if it will be the same in both D1 and D2

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