Ref function pointers?

[Steven Schveighoffer]

On Thu, 06 Jan 2011 22:37:07 -0500, Sean Eskapp <eatingstaples at gmail.com>  
wrote:

> Is there a way to create a function pointer which returns a reference?  
> In all
> the ways I've tried it, my return value becomes "not an lvalue".


int x;
ref int foo()
{
     return x;
}

void main()
{
     auto func = &foo;
     pragma(msg, typeof(func).stringof);
     func() = 5;
}

compiles and outputs during compilation:

int function() ref

However, doing this:

int function() ref func = &foo;

results in an error:

testreffuncptr.d(9): no identifier for declarator int function()
testreffuncptr.d(9): semicolon expected, not 'ref'
testreffuncptr.d(9): found 'ref' instead of statement

So, yes, you can make one.  No you can't specifically type it ;)  You must  
use auto.  I find the type string extremely strange too.

I think this is bugzilla-worthy.

-Steve