Ref function pointers?

[Simen kjaeraas]

Steven Schveighoffer <schveiguy at yahoo.com> wrote:

> On Thu, 06 Jan 2011 22:37:07 -0500, Sean Eskapp  
> <eatingstaples at gmail.com> wrote:
>
>> Is there a way to create a function pointer which returns a reference?  
>> In all
>> the ways I've tried it, my return value becomes "not an lvalue".
>
>
> int x;
> ref int foo()
> {
>      return x;
> }
>
> void main()
> {
>      auto func = &foo;
>      pragma(msg, typeof(func).stringof);
>      func() = 5;
> }
>
> compiles and outputs during compilation:
>
> int function() ref
>
> However, doing this:
>
> int function() ref func = &foo;
>
> results in an error:
>
> testreffuncptr.d(9): no identifier for declarator int function()
> testreffuncptr.d(9): semicolon expected, not 'ref'
> testreffuncptr.d(9): found 'ref' instead of statement
>
> So, yes, you can make one.  No you can't specifically type it ;)  You  
> must use auto.  I find the type string extremely strange too.
>
> I think this is bugzilla-worthy.

It's a known problem, not sure if it is in Bugzilla though.
Workaround:

     alias ref int function() rifn;
     rifn fn = &foo;


-- 
Simen