DIP61: redone to do extern(C++,N) syntax
Byron via Digitalmars-d
digitalmars-d at puremagic.com
Mon Apr 28 07:37:36 PDT 2014
On Mon, 28 Apr 2014 10:27:19 -0400, Steven Schveighoffer wrote:
> On Sun, 27 Apr 2014 15:54:51 -0400, Walter Bright
> <newshound2 at digitalmars.com> wrote:
>
>> http://wiki.dlang.org/DIP61
>
> I think there is a big problem with name lookup here.
>
> Consider this code:
>
> module foo;
>
> void func() {}
>
> module bar;
>
> extern(C) func();
>
> module prog;
>
> import foo;
> import bar;
>
> void main()
> {
> func(); // error foo.func(); // ok bar.func(); // ok, uses C binding
> (no name mangling)
> }
>
> In this case, even though the C function is not mangled or in any other
> namespace, the module can be used for unambiguous calling.
>
> But in your proposal, the name qualifiers could be either C++ namespaces
> or D modules. This presents an unnecessary ambiguity.
>
> e.g.
>
> module foo;
>
> void func() {}
>
> module bar;
>
> extern(C++, foo) void func(); // foo::func in C++ land
>
> module prog;
>
> import foo;
> import bar;
>
> void main()
> {
> func(); // error foo.func(); // ALSO error bar.func(); // Not error,
> BUT it's actually calling foo::func from C++
> land!
> }
>
> I think we cannot change name lookup rules for C++ symbols, because the
> D module system already owns those.
>
> An alternative is that you could create an alternate way to
> disambiguate.
> Let's pick a strawman called _cpp, just to illustrate:
>
> void main()
> {
> func(); // error still foo.func(); // calls D's foo module's func
> bar.func(); // calls D's bar module's func (defined as foo::func)
> _cpp.func(); // error, _cpp denotes we are using namespace
> qualifiers,
> and there is no global C++ func
> _cpp.foo.func(); // calls D's bar module's func.
> bar._cpp.foo.func(); // ditto
> }
>
> Really, _cpp could be anything. But I think hijacking D's module
> qualifiers does not help. To make things seamless, you could make it ::,
> but I know many people have objections to that.
>
> -Steve
why not import _cpp = bar; ?
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